Scientific Notation Exercises

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Scientific notation is used to reduce writing very large numbers using the power of 10.

Test your knowledge with the following questions and clear your doubts with comments in the resolutions.

question 1

Pass the numbers below for scientific notation.

a) 105,000

Correct answer: 1.05 x 105

1st step: Find the value of N walking with the decimal point from right to left until you reach a number less than 10 and greater than or equal to 1.

table row with 1 comma cell with 0 with lower parenthesis below end of cell cell with 5 with lower parenthesis below end of cell cell with 0 with bottom parenthesis below end of cell cell with 0 with bottom parenthesis below end of cell row with blank arrow to up blank blank blank blank end of table table row with cell with 0 with bottom parenthesis below end of cell row with blank end of table

1.05 is the value of N.

Step 2: Find the value of no counting by how many decimal places the comma went.

table row with 1 comma cell with 0 with lower parenthesis below end of cell cell with 5 with lower parenthesis below end of cell cell with 0 with lower parenthesis below end of cell cell with 0 with bottom parenthesis below end of cell row with blank blank cell with 5th end of cell cell with 4th end of cell cell with 3rd end of cell cell with 2nd end of cell end of table table row with cell with 0 with bottom parenthesis below end of cell row with cell with 1st end of cell end of table

5 is the value of no, because the comma has moved 5 decimal places from right to left.

3rd step: Write the number in scientific notation.

The scientific notation formula being N. 10no, the value of N is 1.05 and of n is 5, we have 1.05 x 105.

b) 0.0019

Correct answer: 1.9 x 10-3

1st step: Find the value of N walking with the decimal point from left to right until you reach a number less than 10 and greater than or equal to 1.

table row with 0 cell with 0 with lower parenthesis below end of cell cell with 0 with lower parenthesis below end of cell cell with 1 with bottom parenthesis down end of cell comma row with blank blank blank blank up arrow end of table table row with 9 row with blank end of table

1.9 is the value of N.

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Step 2: Find the value of no counting by how many decimal places the comma went.

table row with 0 cell with 0 with lower parenthesis below end of cell cell with 0 with lower parenthesis below end of cell cell with 1 with lower parenthesis below end of cell comma row with blank cell with 1st end of cell cell with 2nd end of cell cell with 3rd end of cell blank end of table table row with 9 row with blank end of table

-3 is the value of no, because the comma has moved 3 decimal places from left to right.

3rd step: Write the number in scientific notation.

The scientific notation formula being N. 10no, the value of N is 1.9 and of n is -3, we have 1.9 x 10-3.

See too: Cientific notation

question 2

The distance between the Sun and the Earth is 149 600 000 km. How much is this number in scientific notation?

Correct answer: 1.496 x 108 km.

1st step: Find the value of N walking with the decimal point from right to left until you reach a number less than 10 and greater than or equal to 1.

1 space comma space 4 with lower parenthesis below 9 with lower parenthesis below space 6 with lower parenthesis below 0 with lower parenthesis below 0 with lower parenthesis below space 0 with lower parenthesis below 0 with lower parenthesis below 0 with bottom parenthesis below table space row with cell with table space row with up arrow blank end of table end of cell end from the table

1.496 is the value of N.

Step 2: Find the value of no counting by how many decimal places the comma went.

table row with cell with 1 comma end of cell row with blank row with blank end of table table row with cell with 4 with bottom parenthesis below end of cell cell with 9 with bottom parenthesis below end of cell row with cell with 8th end of cell cell with 7th end of cell row with blank end of table table row with cell with 6 with lower parenthesis below end of cell cell with 0 with lower parenthesis below end of cell cell with 0 with lower parenthesis below end of cell cell with 0 with parenthesis bottom below end of cell cell with 0 with bottom parenthesis below end of cell cell with 0 with bottom parenthesis below end of cell row with cell with 6th end of cell cell with 5th end of cell cell with 4th end of cell cell with 3rd end of cell cell with 2nd end of cell cell with 1st end of cell row with blank blank blank blank blank blank end of table

8 is the value of no, because the comma has moved 8 decimal places from right to left.

3rd step: Write the number in scientific notation.

The scientific notation formula being N. 10no, the value of N is 1.496 and of n is 8, we have 1.496 x 108.

question 3

Avogadro's constant is an important quantity that relates the number of molecules, atoms or ions in a mole of substance and its value is 6.02 x 1023. Write this number in decimal form.

Correct answer: 602 000 000 000 000 000 000 000.

Since the exponent of the power of 10 is positive, we must move the decimal point from left to right. The number of decimal places we must walk is 23.

Since after the comma we already have two digits, we must add 21 more digits 0 to complete the 23 positions that the comma has walked. Thus, we have:

6 comma 02 space x space 10 to the power of 23 space equals space 602 space 000 space 000 space 000 space 000 space 000 space 000 space 000 space

Thus, in 1 mole of matter there are 602 sextillions of particles.

question 4

In scientific notation, the mass of an electron at rest corresponds to 9.11 x 10−31 kg and a proton, in the same condition, has a mass of 1.673 x 10-27 kg. Who has the greatest mass?

Correct answer: The proton has greater mass.

By writing the two numbers in decimal form, we have:

electron mass 9.11 x 10−31:

0 comma 000000000000000000000000000000911

proton mass 1,673 x 10-27:

0 comma 0000000000000000000000000001673

Note that the greater the power of 10 exponent, the greater the number of decimal places that make up the number. The minus sign (-) indicates that the counting must be done from left to right and, according to the values ​​presented, the largest mass is that of the proton, as its value is closer to 1.

question 5

One of the smallest forms of life known on Earth lives at the bottom of the sea and is called the nanobe. The maximum size that such a being can reach corresponds to 150 nanometers. Write this number in scientific notation.

Correct answer: 1.5 x 10-7.

Nano is the prefix used to express the billionth part of 1 meter, that is, 1 meter divided by 1 billion corresponds to 1 nanometer.

numerator 1 straight space m over denominator 1 space 000 space 000 space 000 end of fraction equal to 0 comma 000 space 000 space 001 straight space m space equal to space 1 straight space x space 10 to the minus 9 power end of the exponential straight space m

A nanobe can have a length of 150 nanometers, that is, 150 x 10-9 m.

Being 150 = 1.5 x 102, we have:

150 space nm 150 straight space x space 10 to the power of minus 9 end space of the straight exponential m 1 comma 5 straight space x space 10 squared straight space x space 10 to the power of minus 9 end of exponential straight space m 1 comma 5 straight space x space 10 to the power of 2 space plus space left parenthesis minus 9 right parenthesis end of exponential straight space m 1 comma 5 straight space x space 10 to the power of minus 7 end of exponential

The size of a nanobe can also be expressed as 1.5 x 10-7 m. To do this, we move the decimal point by two more decimal places so that the value of N becomes greater than or equal to 1.

See too: units of length

question 6

(Enem/2015) Soy exports in Brazil totaled 4.129 million tons in July 2012 and recorded an increase compared to the month of July 2011, although there was a decrease compared to the month of May of 2012

The quantity, in kilograms, of soy exported by Brazil in July 2012 was:

a) 4,129 x 103
b) 4,129 x 106
c) 4,129 x 109
d) 4,129 x 1012
e) 4,129 x 1015

Correct alternative: c) 4,129 x 109.

We can divide the amount of soy exported into three parts:

4,129 millions tons

Export is given in tons, but the answer must be in kilograms, so the first step to resolve the issue is to convert from tons to kilograms.

1 ton = 1000 kg = 103 kg

There are millions of tons exported, so we must multiply kilograms by 1 million.

1 million = 106

106 x 103 = 106 + 3 = 109

By writing the number of exports in scientific notation, we get 4,129 x 109 kilograms of exported soybeans.

question 7

(Enem/2017) One of the main speed tests in athletics is the 400-meter dash. At the World Championships in Seville, in 1999, the athlete Michael Johnson won this race, with the mark of 43.18 seconds.

This second time, written in scientific notation is

a) 0.4318 x 102
b) 4.318 x 101
c) 43.18 x 100
d) 431.8 x 10-1
e) 4 318 x 10-2

Correct alternative: b) 4.318 x 101

Although all alternative values ​​are ways to represent the 43.18 second mark, only alternative b is correct, as it obeys the rules of scientific notation.

The format used to represent numbers is N. 10no, Where:

  • N represents a real number greater than or equal to 1 and less than 10.
  • The n is an integer that corresponds to the number of decimal places that the comma "walked".

Scientific notation 4.318 x 101 represents 43.18 seconds, as the power raised to 1 results in the base itself.

4.318 x 101 = 4.318 x 10 = 43.18 seconds.

question 8

(Enem/2017) Measuring distances has always been a human need. Over time, it became necessary to create measurement units that could represent such distances, such as the meter. A little known unit of length is the Astronomical Unit (AU), used to describe, for example, distances between celestial bodies. By definition, 1 AU is equivalent to the distance between the Earth and the Sun, which in scientific notation is given as 1.496 x 102 millions of kilometers.

In the same form of representation, 1 AU, in meter, is equivalent to

a) 1.496 x 1011 m
b) 1.496 x 1010 m
c) 1.496 x 108 m
d) 1.496 x 106 m
e) 1.496 x 105 m

Correct alternative: a) 1.496 x 1011 m.

To resolve this issue you need to remember that:

  • 1 km has 1000 meters, which can be represented by 103 m.
  • 1 million corresponds to 1 000 000, which is represented by 106 m.

We can find the distance between the Earth and the Sun using the rule of three. To solve this question, we use the multiplication operation in scientific notation, repeating the base and adding the exponents.

table row with cell with 1 space km end of cell minus cell with 10 cubed straight space m end of cell blank blank row with cell with 1 comma 496 space. space 10 squared.10 to power of 6 space km end of cell minus straight x blank blank row with blank blank blank blank blank row with straight x equal to cell with numerator 1 comma 496 space. space 10 squared.10 to the power of 6 space crossed out diagonally upwards over km space end of lined out. space 10 cubed space straight m over denominator 1 space diagonal up risk km end fraction end of cell blank blank row with straight x equals cell with 1 comma 496 space. space 10 to the power of 2 plus 6 plus 3 end of straight exponential m end of cell blank blank row with straight x equal to cell with 1 comma 496 space. space 10 to the power of 11 straight space m end of cell blank blank end of table

See too: Potentiation

question 9

Perform the following operations and write the results in scientific notation.

a) 0.00004 x 24 000 000
b) 0.0000008 x 0.00120
c) 2 000 000 000 x 30 000 000 000

All alternatives involve the multiplication operation.

An easy way to solve them is to put the numbers in the form of scientific notation (N. 10no) and multiply the values ​​of N. Then, for the powers of base 10, the base is repeated and the exponents are added.

a) Correct answer: 9.60 x 102

0 comma 00004 straight space x space 24 space 000 space 000 4 straight space x space 10 to the minus 5 end of the straight exponential x space 2 comma 4 straight space x space 10 to the power of 7 4 straight space x space 2 comma 4 straight space x space 10 to the power of minus 5 plus 7 end of exponential 9 comma 6 straight space x space 10 ao square

b) Correct answer: 9.6 x 10-10

0 comma 0000008 straight space x space 0 comma 00120 8 straight space x space 10 to the minus 7 end power of the straight exponential x space 1 comma 20 straight space x space 10 to the minus power 3 end of the exponential 8 straight space x space 1 comma 20 straight space x space 10 to the minus power 7 plus left parenthesis minus 3 right parenthesis end of exponential 9 comma 60 straight space x space 10 to the minus 10 power end of exponential

c) Correct answer: 6.0 x 1019

2 space 000 space 000 space 000 space x space 30 space 000 space 000 space 000 2 comma 0 straight space x space 10 to the power of 9 space end of straight exponential x space 3 comma 0 space straight x space 10 to the power of 10 2 comma 0 straight space x space 3 comma 0 straight space x space 10 to the power of 9 plus 10 end of exponential 6 comma 0 straight space x space 10 to the power of 19

See too order of magnitude

question 10

(UNIFOR) A number expressed in scientific notation is written as the product of two real numbers: one of them, belonging to the interval [1,10[, and the other, a power of 0. So, for example, the scientific notation of the number 0.000714 is 7.14 × 10–4. According to this information, the scientific notation of the number straight N space equal to space numerator 0 comma 000243 space multiplication sign space 0 comma 0050 space over denominator 0 comma 036 space multiplication sign space 7 comma space 5 space end of fraction é

a) 40.5 x 10–5
b) 45 x 10–5
c) 4.05 x 10–6
d) 4.5 x 10–6
e) 4.05 x 10–7

Correct alternative: d) 4.5 x 10–6

To resolve the issue, we can rewrite the numbers in the form of scientific notation.

straight N space equal to space numerator 0 comma 000243 space multiplication sign space 0 comma 0050 space over denominator 0 comma 036 space multiplication sign space 7 comma 5 space end of fraction straight N space equal to numerator space 2 comma 43 straight space x space 10 à minus 4 end power of the exponential straight space x space 5 comma 0 straight space x space 10 to the minus 3 end power of the exponential over denominator 3 comma 6 straight space x space 10 to the minus power 2 end of exponential straight space x space 7 comma 5 straight space x space 10 à power of 0 end of fraction

In the multiplication operation of powers of the same base, we add the exponents.

straight N space equal to numerator 2 comma 43 straight space x space 5 comma 0 space 10 to the power of minus 4 end of the exponential straight space x space 10 to the power of minus 3 end of exponential over denominator 3 comma 6 straight space x space 7 comma 5 straight space x space 10 to the power of minus 2 end of exponential straight space x space 10 to the power of 0 end of the fraction straight N space equal to numerator 12 comma 15 straight space x space 10 to the power of minus 4 plus left parenthesis minus 3 right parenthesis end of exponential over denominator 27 straight space x space 10 to the power of minus 2 plus 0 end of exponential end of fraction straight N space equal to numerator 12 comma 15 straight space x space 10 to the minus 7 power end of the exponential over denominator 27 straight space x 10 space to the minus 2 end of the exponential end of fraction

In the division of powers, we repeat the base and subtract the exponents.

straight N space 0 comma 45 straight space x space 10 to the power of minus 7 minus left parenthesis minus 2 parenthesis right end of straight exponential N space equal to 0 point 45 straight space x space 10 to the minus 5 power end of exponential

We then pass the result to scientific notation.

straight N space equal to space 4 comma 5 straight space x space 10 to the minus 6 end of the exponential
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