MMC and MDC: Learn a simple and easy way to calculate them simultaneously

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The least common multiple (MMC or M.M.C) and the greatest common divisor (MDC or M.D.C) can be calculated simultaneously by decomposing into prime factors.

Through factorization, the MMC of two or more numbers is determined by multiplying the factors. The MDC, on the other hand, is obtained by multiplying the numbers that divide them at the same time.

1st step: factoring the numbers

Factorization consists of representing prime numbers, which are called factors. For example, 2 x 2 is the factored shape of 4.

The factored form of a number is obtained by following the sequence:

  • It starts with division by the smallest possible prime number;
  • The quotient of the previous division is also divided by the smallest possible prime number;
  • The division is repeated until the result is number 1.

Example: factoring the number 40.

40 | 2 → 40: 2 = 20, since 2 is the smallest possible prime divisor and the division quotient is 20.
20 | 2 → 20: 2 = 10, since 2 is the smallest possible prime divisor and the division quotient is 10.

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10 | 2 → 10: 2 = 5, since 5 is the smallest possible prime divisor and the division quotient is 5.
5 | 5 → 5: 5 = 1, since 5 is the smallest possible prime divisor and the division quotient is 1.
1

So the factored form of the number 40 is 2 x 2 x 2 x 5, which is the same as 23 x 5.

Learn more about Prime numbers.

2nd step: MMC calculation

Decomposing two numbers simultaneously will result in the factored form of the least common multiple between them.

Example: factoring the numbers 40 and 60.

table row with 40 60 row with 20 30 row with 10 15 row with 5 15 row with 5 5 row with 1 1 end of table in right frame closes table frame row with 2 row with 2 row with 2 row with 3 row with 5 row with blank end of table

The multiplication of prime factors 2 x 2 x 2 x 3 x 5 has a factored form 23 x 3 x 5.

Therefore, the MMC of 40 and 60 is: 23 x 3 x 5 = 120.

Remember that the divisions will always be done by the smallest possible prime number, even if this number only divides one of the components.

Learn more about Least common multiple.

3rd step: MDC calculation

The greatest common divisor is found when we multiply the factors that simultaneously divide the factored numbers.

In factoring 40 and 60, we can see that number 2 was able to divide the division quotient twice and number 5 once.

table row with bold 40 bold 60 row with bold 20 bold 30 row with 10 15 row with 5 15 row with bold 5 bold 5 row with 1 1 end of table in right frame closes frame table line with bold 2 line with bold 2 line with 2 line with 3 line with bold 5 line with blank end of table

Therefore, the MDC of 40 and 60 is: 22 x 5 = 20.

Learn more aboutMaximum Common Divider.

Practicing MMC and MDC calculations

Exercise 1: 10, 20 and 30

Correct answer: MMC = 60 and MDC = 10.

1st step: decomposition into prime factors.

Divide by the smallest possible prime numbers.

table row with 10 20 30 row with 5 10 15 row with 5 5 15 row with 5 5 5 row with 1 1 1 end of table in right frame closes table frame row with 2 row with 2 row with 3 row with 5 row with blank end of table

2nd step: MMC calculation.

Multiply the factors found above.

MMC: 2 x 2 x 3 x 5 = 22 x 3 x 5 = 60

3rd step: calculation of the MDC.

Multiply the factors that divide the numbers at the same time.

table row with bold 10 bold 20 bold 30 row with 5 10 15 row with 5 5 15 row with bold 5 bold 5 bold 5 row with 1 1 1 end of table in right frame closes table frame line with bold 2 line with 2 line with 3 line with bold 5 line with blank end of table

MDC: 2 x 5 = 10

Exercise 2: 15, 25 and 45

Correct answer: MMC = 225 and MDC = 5.

1st step: decomposition into prime factors.

Divide by the smallest possible prime numbers.

table row with 15 25 45 row with 5 25 15 row with 5 25 5 row with 1 5 1 row with 1 1 1 end of table at right frame closes table frame row with 3 row with 3 row with 5 row with 5 row with blank end of table

2nd step: MMC calculation.

Multiply the factors found above.

MMC: 3 x 3 x 5 x 5 = 32 x 52 = 225

3rd step: MDC calculation

Multiply the factors that divide the numbers at the same time.

table row with 15 25 45 row with 5 25 15 row with bold 5 bold 25 bold 5 row with 1 5 1 row with 1 1 1 end of table in right frame closes frame table line with 3 line with 3 line with bold 5 line with 5 line with blank end of table

MDC: 5

See too: Multiples and Dividers

Exercise 3: 40, 60 and 80

Correct answer: MMC = 240 and MDC = 20.

1st step: decomposition into prime factors.

Divide by the smallest possible prime numbers.

table row with 40 60 80 row with 20 30 40 row with 10 15 20 row with 5 15 10 row with 5 15 5 row with 5 5 5 row with 1 1 1 end of table in right frame closes frame table line with 2 line with 2 line with 2 line with 2 line with 3 line with 5 line with blank end of table

2nd step: MMC calculation.

Multiply the factors found above.

MMC: 2 x 2 x 2 x 2 x 3 x 5 = 24 x 3 x 5 = 240

3rd step: calculation of the MDC.

Multiply the factors that divide the numbers at the same time.

table row with bold 40 bold 60 bold 80 row with bold 20 bold 30 bold 40 row with 10 15 20 row with 5 15 10 row with 5 15 5 row with bold 5 bold 5 bold 5 line with 1 1 1 end of table in right frame closes frame line with bold 2 line with bold 2 line with 2 line with 2 line with 3 line with bold 5 line with blank end of table

MDC: 2 x 2 x 5 = 22 x 5 = 20

For more issues with commented resolution, see also: MMC and MDC - Exercises.

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