Compound rule of three: learn to calculate (with step by step and exercises)

Compound rule of three is a mathematical process used in solving questions involving direct or inverse proportionality with more than two quantities.

How to make the rule of three compound

To solve a compound rule of three question, you basically need to follow these steps:

  • Check what are the quantities involved;
  • Determine the type of relationship between them (direct or inverse);
  • Perform calculations using the data provided.

Here are some examples that will help you understand how this should be done.

Rule of three composed with three magnitudes

If to feed a family of 9 people for 25 days 5 kg of rice is needed, how many kg would it take to feed 15 people for 45 days?

1st step: Group the values ​​and organize the statement data.

People Days Rice (kg)
THE B Ç
9 25 5
15 45 X

2nd step: Interpret whether the proportion between the quantities is direct or inverse.

Analyzing the question data, we see that:

  • A and C are directly proportional quantities: the more people, the greater the amount of rice needed to feed them.
  • B and C are directly proportional quantities: the more days that pass, the more rice will be needed to feed people.

We can also represent this relationship through arrows. By convention, we insert the down arrow in the ratio containing the unknown X. Since the proportionality is direct between C and quantities A and B, then the arrow in each quantity has the same direction as the arrow in C.

table row with 9 row with 15 end of table arrow down table row with 25 row with 45 end of table arrow down table row with 5 row with straight X end of table arrow down

3rd step: Equalize quantity C to the product of quantities A and B.

as all greatnesses are directly proportional to C, then the multiplication of its ratios corresponds to the ratio of the magnitude of the unknown X.

5 over straight X equals 9 over 15.25 over 45 5 over straight X equals 225 over 675 225 space. straight space X space equals space 5 space. space 675 straight X space equal to space numerator 3 space 375 over denominator 225 end of fraction straight X space equal to space 15

Therefore, 15 kg of rice are needed to feed 15 people for 45 days.

See too: ratio and proportion

Rule of three composed with four magnitudes

In a print shop there are 3 printers that work 4 days, 5 hours a day, and produce 300,000 prints. If one machine needs to be taken out for maintenance and the remaining two machines work for 5 days, making 6 hours a day, how many prints will be produced?

1st step: Group the values ​​and organize the statement data.

Printers Days hours Production
THE B Ç D
3 4 5 300 000
2 5 6 X

2nd step: Interpret the type of proportionality between the quantities.

We must relate the quantity that contains the unknown with the other quantities. By observing the question data, we can see that:

  • A and D are directly proportional quantities: the more printers working, the greater the number of prints.
  • B and D are directly proportional quantities: the more days working, the greater the number of impressions.
  • C and D are directly proportional quantities: the more hours you work, the greater the number of impressions.

We can also represent this relationship through arrows. By convention, we insert the down arrow in the ratio containing the unknown X. As the quantities A, B and C are directly proportional to D, then the arrow in each quantity has the same direction as the arrow in D.

table row with 3 row with 2 end of table arrow down table row with 4 row with 5 end of table arrow down table row with 5 row with 6 end of table arrow down table row with cell with 300 space 000 end of cell row with straight X end of table arrow to low

3rd step: Equate quantity D to the product of quantities A, B and C.

as all greatnesses are directly proportional to D, then the multiplication of its ratios corresponds to the ratio of the magnitude of the unknown X.

numerator 300 space 000 over straight denominator X end of fraction equal to 3 over 2.4 over 5.5 over 6 numerator 300 space 000 over straight denominator X end of fraction equal to 60 over 60 60 spaces. straight space X space equals space 60 space. space 300 space 000 straight X space equal to numerator 18 space 000 space 000 over denominator 60 end of fraction straight X narrow space equal to space 300 space 000

If two machines work 5 hours for 6 days the number of impressions will not be affected, they will continue producing 300 000.

See too: Simple and Compound Three Rule

Solved exercises on compound rule of three

question 1

(Unifor) A text occupies 6 pages of 45 lines each, with 80 letters (or spaces) on each line. To make it more readable, the number of lines per page is reduced to 30 and the number of letters (or spaces) per line reduced to 40. Considering the new conditions, determine the number of pages occupied.

Correct answer: 2 pages.

The first step to answer the question is to verify the proportionality between the quantities.

lines Letters Pages
THE B Ç
45 80 6
30 40 X
  • A and C are inversely proportional: the fewer lines on a page, the more pages to occupy all the text.
  • B and C are inversely proportional: the fewer letters on a page, the greater the number of pages to occupy all the text.

Using arrows, the relationship between the quantities is:

table row with cell with table row with 45 row with 30 end of table end of cell end of table up arrow table row with cell with table row with 80 row with 40 end table end cell end table up arrow table row with cell with table row with 6 row with straight X end of table end of cell end of table arrow to low

To find the value of X we must invert the ratios of A and B, since these quantities are inversely proportional,

6 over straight X equals 30 over 45.40 over 80 arrow in northwest position Inverse space ratios 6 over straight X equals numerator 1 space 200 over denominator 3 space 600 end of fraction 1 space 200 space. straight space X space equals space 6 space. space 3 space 600 straight X space equal to space numerator 21 space 600 over denominator 1 space 200 end of fraction straight X space equal to space 18

Considering the new conditions, 18 pages will be used.

question 2

(Vunesp) Ten employees of a department work 8 hours a day, for 27 days, to serve a certain number of people. If a sick employee has been on leave indefinitely and another has retired, the total number of days the employees remaining will take to serve the same number of people, working an extra hour a day, at the same work rate, it will be

a) 29
b) 30
b) 33
d) 28
e) 31

Correct alternative: b) 30

The first step to answer the question is to verify the proportionality between the quantities.

Employees hours Days
THE B Ç
10 8 27
10 - 2 = 8 9 X
  • A and C are inversely proportional quantities: fewer employees will take more days to serve everyone.
  • B and C are inversely proportional quantities: more hours worked per day will mean that in fewer days all people are served.

Using arrows, the relationship between the quantities is:

10 on 8 up arrow table row with 8 row with 9 end of table up arrow table row with 27 row with straight X end of table down arrow

Since the quantities A and B are inversely proportional, to find the value of X, we must invert their ratios.

Error converting from MathML to accessible text.

Thus, in 30 days, the same number of people will be served.

question 3

(Enem) An industry has a water reservoir with a capacity of 900 m3. When there is a need to clean the reservoir, all the water needs to be drained. The drainage of water is done by six drains, and lasts 6 hours when the reservoir is full. This industry will build a new reservoir, with a capacity of 500 m3, whose water must be drained within 4 hours, when the reservoir is full. The drains used in the new reservoir must be identical to the existing ones.

The amount of drains in the new reservoir should be equal to

a) 2
b) 4
c) 5
d) 8
e) 9

Correct alternative: c) 5

The first step to answer the question is to verify the proportionality between the quantities.

Reservoir (m3) Flow (h) drains
THE B Ç
900 m3 6 6
500 m3 4 X
  • A and C are directly proportional quantities: if the reservoir capacity is smaller, fewer drains will be able to carry out the flow.
  • B and C are inversely proportional quantities: the shorter the flow time, the greater the number of drains.

Using arrows, the relationship between the quantities is:

900 over 500 down arrow table row with 6 row with 4 end of table up arrow table row with 6 row with straight X end of table down arrow

As the quantity A is directly proportional, its ratio is maintained. On the other hand, magnitude B has its ratio inverted because it is inversely proportional to C.

6 over straight X equal to 900 over 500.4 over 6 arrow in northwest position Inverse space ratio 6 over straight X equal to numerator 3 space 600 over denominator 3 space 000 end of fraction 3 space 600 space. straight space X space equals space 6 space. space 3 space 000 straight X space equal to space numerator 18 space 000 over denominator 3 space 600 end of fraction straight X space equal to space 5

Thus, the amount of drains in the new reservoir should be equal to 5.

Keep practicing with the exercises:

  • Three Compound Rule Exercises
  • Simple Three Rule Exercises
  • Rule of Three Exercises
  • Exercises on reason and proportion

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