Sphere volume: how to calculate?

O sphere volume is the space occupied by this geometric solid. Through the ray of ball — that is, from the distance between the center and the surface — it is possible to calculate its volume.

Read too: Volume of geometric solids

Summary about the volume of the sphere

  • The sphere is a round body obtained by revolving a semicircle around an axis containing the diameter.

  • All points on a sphere are at a distance equal to or less than r from the center of the sphere.

  • The volume of the sphere depends on the measure of the radius.

  • The formula for the volume of the sphere is \(V=\frac{4·π·r^3}3\)

Video lesson on the volume of the sphere

What is sphere?

Consider a point O in space and a segment with measure r. the sphere is the solid formed by all points that are at a distance equal to or less than r from O. We call O the center of the sphere and r the radius of the sphere.

Representation of a sphere and its radius.

the sphere can also be characterized as a solid of revolution. Note that rotating a semicircle about an axis containing its diameter forms a sphere:

Representation of the rotation of a semicircle to form a sphere.

Sphere volume formula

To calculate the volume V of a sphere, we use the formula below, where r is the radius of the sphere:

\(V=\frac{4·π·r^3}{3}\)

It is important to observe the unit of measurement radius to determine the unit of measure for volume. For example, if r is given in cm, then the volume must be given in cm³.

How to calculate the volume of the sphere?

The calculation of the volume of the sphere depends only on the measurement of the radius. Let's look at an example.

Example: Using the approximation π = 3, find the volume of a basketball that is 24 centimeters in diameter.

Since the diameter is twice the radius, r = 12 cm. Applying the formula for the volume of the sphere, we have

\(V=\frac{4·π·12^3}3\)

\(V=\frac{4 · π·1728}3\)

\(V=6 912\ cm^3\)

sphere regions

Consider a sphere with center O and radius r. Like this, we can consider three regions of this sphere:

  • The inner region is formed by the points whose distance from the center is less than the radius. If P belongs to the inner region of the sphere, then

\(D(P, O)

  • The surface region is formed by the points whose distance from the center is equal to the radius. If P belongs to the surface region of the sphere, then

\(D(P, O)=r\)

  • The outer region is formed by the points whose distance from the center is greater than the radius. If P belongs to the inner region of the sphere, then

\(D(P, O)>r\)

Consequently, points on the outer region of the sphere do not belong to the sphere.

Know more: Spherical cap — solid obtained when a sphere is intersected by a plane

Other sphere formulas

A sphere area — that is, the measurement of its surface — also has a known formula. If r is the radius of the sphere, its area A is calculated by

\(A=4·π·r^2\)

In this case, it is also important to note the unit of measurement for the radius to indicate the unit of measurement for the area. For example, if r is in cm, then A must be in cm².

Solved exercises on the volume of the sphere

question 1

What is the radius of a sphere that has a volume of 108 cubic centimeters? (Use π = 3).

a) 2 cm

b) 3 cm

c) 4 cm

d) 5 cm

e) 6 cm

Resolution

Alternative B.

Consider that r is the radius of the sphere. Knowing that V = 108, we can use the formula for the volume of the sphere:

\(V=\frac{4·π·r^3}3\)

\(108=\frac{4·3·r^3}3\)

\(108=4·r^3\)

\(r^3=27\)

\(r = 3\ cm\)

question 2

An ancient spherical reservoir is 20 meters in diameter and has a volume V1. It is desired to build a second reservoir, of volume V2, with twice the volume of the old reservoir. So, V2 it's the same as

The) \(\frac{3000·π}{8} m^3\)

B) \(\frac{3000·π}{4} m^3\)

w) \(\frac{2000·π}{3} m^3\)

d) \(\frac{4000·π}{3} m^3\)

It is) \(\frac{8000·π}{3} m^3\)

Resolution

E alternative.

As the diameter is twice the radius, the old reservoir has radius r = 10 meters. Therefore

\(V_1=\frac{4·π·r^3}3\)

\(V_1=\frac{4·π·10^3}3\)

\(V_1=\frac{4000·π}3\ m^3\)

By the statement, \(V_2=2·V_1\), i.e

\(V_2=\frac{8000·π}3 m^3\)

By Maria Luiza Alves Rizzo
Math teacher

Source: Brazil School - https://brasilescola.uol.com.br/matematica/volume-da-esfera.htm

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