Concept and Calculation of Probability

THE probability theory is the branch of Mathematics that studies experiments or random phenomena and through it it is possible to analyze the chances of a certain event occurring.

When we calculate probability, we are associating a degree of confidence that the possible results of experiments will occur, the results of which cannot be determined in advance.

In this way, the probability calculation associates the occurrence of a result to a value that varies from 0 to 1 and, the closer the result is to 1, the greater the certainty of its occurrence.

For example, we can calculate the probability that a person will buy a winning lottery ticket or know the odds that a couple will have 5 children, all boys.

probability

random experiment

A random experiment is one that cannot predict what result will be found before carrying it out.

Events of this type, when repeated under the same conditions, can give different results and this inconstancy is attributed to chance.

An example of a random experiment is to roll an unbiased die (die that has a homogeneous mass distribution) upwards. When falling, it is not possible to predict with certainty which of the 6 faces will be facing upwards.

Probability Formula

In a random phenomenon, the chances of an event occurring are equally likely.

Thus, we can find the probability of a given result occurring by dividing the number of favorable events and the total number of possible outcomes:

bold italic p bold left parenthesis bold italic A bold right parenthesis bold equals numerator bold n bold left parenthesis bold A bold right parenthesis on denominator bold n bold left parenthesis bold omega capital bold right parenthesis end of fraction

Being:

p(A): probability of occurrence of an event A
at): number of cases that interest us (event A)
n (Ω): total number of possible cases

Examples

1) If we roll a perfect die, what is the probability that a number less than 3 will roll?

Dice

Solution

As the perfect die, all 6 faces have an equal chance of falling face-up. So let's apply the probability formula.

For this, we must consider that we have 6 possible cases (1, 2, 3, 4, 5, 6) and that the event "out of a number less than 3" has 2 possibilities, that is, out of the number 1 or the number 2. So we have:

p left parenthesis Right parenthesis equals numerator n left parenthesis Right parenthesis over denominator n left parenthesis omega capital right parenthesis end of fraction P equal to 2 over 6 equal to 1 third P approximately equal 0 comma 33 approximately equal 33 sign of percentage

2) The deck of cards consists of 52 cards divided into four suits (hearts, clubs, diamonds and spades) with 13 cards of each suit. Thus, if you draw a card at random, what is the probability of a card coming out of the club suit?

Playing cards

Solution

When drawing a card at random, we cannot predict what this card will be. So this is a random experiment.

In this case, the number of cards corresponds to the number of possible cases and we have 13 clubs that represent the number of favorable events.

Substituting these values ​​in the probability formula, we have:

p left parenthesis Right parenthesis equals numerator n left parenthesis Right parenthesis over denominator n left parenthesis omega uppercase parenthesis right end of fraction p left parenthesis Right parenthesis equals 13 out of 52 p left parenthesis Right parenthesis equals 0 comma 25 equals 25 sign of percentage

Sample space

represented by the letter Ω, the sample space corresponds to the set of possible results obtained from a random experiment.

For example, when randomly taking a card from a deck, the sample space corresponds to the 52 cards that make up this deck.

Likewise, the sample space when rolling a die once, are the six faces that compose it:

Ω = {1, 2, 3, 4, 5 and 6}.

Types of Events

The event is any subset of the sample space of a random experiment.

When an event is exactly the same as its sample space, it is called a right event. Conversely, when the event is empty, it is called a impossible event.

Example

Imagine that we have a box with balls numbered from 1 to 20 and that all the balls are red.

The "draw a red ball" event is a sure event, as all the balls in the box are of this color. The "draw a number greater than 30" event is impossible, since the highest number in the box is 20.

Combinatorial Analysis

In many situations, it is possible to directly discover the number of possible and favorable events in a random experiment.

However, in some problems you will need to calculate these values. In this case, we can use the permutation, arrangement and combination formulas according to the situation proposed in the question.

To learn more about the topic, go to:

  • Combinatorial Analysis
  • Combinatorial Analysis Exercises
  • Fundamental Principle of Counting
  • Permutation

Example

(EsPCEx - 2012) The probability of obtaining a number divisible by 2 in the random choice of one of the permutations of the digits 1, 2, 3, 4, 5 is

a right parenthesis 1 fifth b right parenthesis 2 over 5 c right parenthesis space 3 over 4 d right parenthesis 1 fourth and right parenthesis 1 middle

Solution

In this case, we need to find out the number of possible events, that is, how many different numbers we get by changing the order of the given 5 digits (n=5).

As, in this case, the order of the digits form different numbers, we will use the permutation formula. Therefore, we have:

Possible events: P with 5 subscript equal to n factorial space equal to 5 factorial equal to 5.4.3.2.1 equal to 120

Therefore, with 5 digits we can find 120 different numbers.

To calculate the probability, we still have to find the number of favorable events that, in this case, is to find a number divisible by 2, which will happen when the last digit of the number is 2 or 4.

Considering that for the last position we only have these two possibilities, then we will have to swap the other 4 positions that make up the number, like this:

Favorable events: 2. P with 4 subscript space equal to space 2. space 4 factorial space equal to space 2.4.3.2.1 equal to 48

The probability will be found by doing:

p left parenthesis Right parenthesis equals 48 over 120 equals 2 over 5

Read too:

  • Pascal's triangle
  • Complex numbers
  • Mathematics in Enem

Exercise solved

1) PUC/RJ - 2013

If a = 2n + 1 with n ∈ {1, 2, 3, 4}, then the probability of the number The being a pair is

to 1
b) 0.2
c) 0.5
d) 0.8
e) 0

As we substitute every possible value of n into the expression for the number a, we notice that the result will always be an odd number.

Therefore, "being an even number" is an impossible event. In this case, the probability is equal to zero.

Alternative: e) 0

2) UPE - 2013

In a group of a Spanish course, three people intend to do an exchange program in Chile, and seven in Spain. Among these ten people, two were chosen for the interview that will draw scholarships for study abroad. The probability that these two chosen people belong to the group of those who intend to do an exchange in Chile is

a right parenthesis space 1 fifth b right parenthesis space 1 over 15 c right parenthesis space 1 over 45 d right parenthesis space 3 over 10 and right parenthesis space 3 over 7

First, let's find the number of possible situations. As the choice of the 2 people does not depend on the order, we will use the combination formula to determine the number of possible cases, ie:

C with 10 comma 2 subscript end of subscript equal to numerator 10 factorial over denominator 2 factorial space left parenthesis 10 minus 2 right parenthesis factorial end of fraction equal to numerator 10 factorial over denominator 2 factorial space 8 factorial end of fraction equal to numerator 10.9. crossed out diagonal to top over 8 factorial end of crossed out over denominator 2.1. diagonal strike up over 8 factorial end of strikeout end of fraction equal to 90 over 2 equal to 45

So there are 45 ways to choose 2 people out of a group of 10 people.

Now, we need to calculate the number of favorable events, that is, the two people drawn want to do the exchange in Chile. Again we will use the combination formula:

C with 3 comma 2 subscript end of subscript equal to numerator 3 factorial over denominator 2 factorial space left parenthesis 3 minus 2 right parenthesis factorial end of fraction equal to numerator 3. diagonal strikeout up over 2 factorial end of strikeout over denominator diagonal strikeout up over 2 factorial end of strikeout space 1 end of fraction equal to 3

So there are 3 ways to choose 2 people out of the 3 who want to study in Chile.

With the values ​​found, we can calculate the requested probability substituting in the formula:

p left parenthesis Right parenthesis equals numerator n left parenthesis Right parenthesis over denominator n parenthesis left omega capital right parenthesis end of fraction p left parenthesis Right parenthesis equals 3 over 45 equals 1 over 15

Alternative: b) 1 over 15

Read more about some related subjects:

  • Newton's binomial
  • Probability Exercises (easy)
  • Probability Exercises
  • Statistic
  • Statistics - Exercises
  • Math Formulas

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