Concept and determination of pH and pOH

pH represents the hydrogen ionic potential and pOH is the hydroxy ionic potential of the solutions.

These are logarithmic scales used to measure the acidic and basic character of a sample.

The values ​​that compose them range from 0 to 14 and were obtained from the ionic balance of water.

A neutral solution has a pH of 7. Values ​​below 7 classify the solutions as acidic, while after 7 the solutions are basic.

With the pH value, it is possible to find the corresponding one on the pOH scale, just by making a subtraction.

Ionic water balance

A water molecule has the ability to ionize according to the equation:

straight H with 2 subscript straight O with left parenthesis straight 1 right parenthesis space subscript end of subscript harpoon to right over harpoon to left straight space H with parenthesis left aq right parenthesis subscript end of subscript with more superscript space more OH space with left parenthesis aq right parenthesis subscript end of subscript with minus envelope

Here we have an ionic balance, because the process is reversible and the ions can also come together and form a water molecule again.

Another way to demonstrate the balance that occurs is through the autoionization.

table row with bold H bold less bold O row with blank blank blank blank row with blank blank blank blank blank end of table table space row with cell with space more space end of cell row with blank row with blank end of table table row with bold H bold less bold O bold less bold H row with blank blank blank blank row with blank blank blank blank blank end of table row with cell with space harpoon space to right about harpoon left space space space end of cell row with blank row with blank end of table space open square brackets table row with cell with table row with bold H bold less bold The less bold bold H end of table end of cell row down arrow row bold H end of table closes square brackets table space row with more row with blank row with blank end of table table row with cell with bold OH to the power of bold minus end of cell row with blank row with blank end of table

A water molecule generated hydronium ions (H3O+) and hydroxyl (OH-) through the disruption of a second molecule.

2 straight H with 2 straight O subscript with left parenthesis straight 1 right parenthesis space subscript end of harpoon subscript to right about harpoon left straight space H with 3 straight subscript O with left parenthesis aq right parenthesis subscript end of subscript with more superscript space more space OH with left parenthesis aq right parenthesis subscript end of subscript with less superscript

Ionic product of water (Kw)

The constant for the ionic balance of water is:

straight K with straight c subscript space equal to numerator space left square bracket straight H with 3 square subscript O to the power of plus right square bracket space. space left square bracket OH to the power of minus right square bracket space over denominator left square bracket H with 2 square subscript The right square bracket squared space end of fraction

As water is a pure liquid, its concentration is taken as 1 and does not interfere with the constant value. Therefore, the expression becomes:

straight K with straight c subscript space. space left square bracket H with 2 straight subscript The right square bracket squared equal the left square bracket H with 3 square subscript O to the power of plus right square bracket space. space left square bracket OH to the power of minus right square bracket space square space K with straight c subscript space. space 1 squared equals left square bracket H with 3 square subscript O to the power of plus right square bracket space. space left square bracket OH to the power of minus right square bracket space square space K with straight c subscript space equal to left square bracket H with 3 straight subscript O to the power of plus square bracket right space. space left square bracket OH to the power of minus right square bracket space space

O ionic product of Water é left square bracket H with 3 square subscript O to the power of plus right square bracket space. left square bracket space OH to the power of minus right square bracket .

This expression receives the symbol Kw (W comes from the English word water - water) and like the equilibrium constant, it varies with temperature.

straight K with straight w subscript space equal to left bracket straight H with 3 straight subscript O to the power of plus right bracket space. left square bracket space OH to the power of minus right square bracket
kW and temperature
Source: K. W. Whitten et al. General Chemistry. 6. ed. Orlando, Saunders, 2000. P. 755.

Determination of pH and pOH

At a temperature of 25°C, the ionic product of water is:

straight K with straight w subscript space equal to space parenthesis left straight straight H with 3 subscript straight O to the power of plus right parenthesis space. space left square bracket OH to the power of minus right square bracket space equals space 1 comma 0 space. space 10 to the power of minus 14 end of exponential

In the ionization of pure water, 1 mol of H3O+ is formed with 1 mol of OH- .

Soon, left square bracket H with 3 square subscript O to the power of plus right square bracket space equal to space left square bracket OH to the power of minus right square bracket space equals 1 comma 0 space. space 10 to the power of minus 7 end of exponential mol space divided by straight L

As these values ​​are extremely low, it was decided to use the values ​​of cologarithms, which correspond to the logarithm with a swapped sign.

pX equals collog straight space X space equals space minus log space straight space X equals numerator 1 over denominator log straight space X end of fraction

Applying the cologarithm to the ionic product of water, we have to:

table row with cell with - log [ straight H to the power of more parenthesis right straight space in box frame close frame end of cell blank cell with less space log space left square bracket OH to the power of least right square bracket space in box frame close frame end of cell equal to cell with less space log space straight K with straight w subscript end of cell row with pH plus cell with pOH space end of cell equal to 14 end of table

We can observe that: if we know the pH of a solution, the pOH value can be found by subtracting the first value from 14.

Acidity and basicity of solutions

Neutral solution: the concentration of hydronium ions is equal to that of hydroxyls.

[H3O+] = 1,0. 10-7 mol/L pH = 7
[oh-] = 1,0. 10-7 mol/L pOH = 7

Example: pure water.

acid solution: the concentration of hydronium ions is greater than that of hydroxyls.

[H3O+] bigger then1,0. 10-7 mol/L pH less than 7
[oh-] less than 1,0. 10-7 mol/L pOH bigger then7

Example: soda, lemon and tomato.

basic solution: the concentration of hydroxyls is greater than that of hydronium ions.

[H3O+] less than1,0. 10-7 mol/L pH bigger then 7
[oh-] bigger then 1,0. 10-7 mol/L pOH less than 7

Example: egg, soap and bleach.

pH scale

pH calculation

The concept of hydrogenic potential was created by the Danish chemist Peter Lauritz Sorensen (1868-1939) to express the acidity of a solution through the concentration of H+.

See the table below demonstrating the ionization of a acid:

bold space bold space bold space bold space bold space bold space bold space bold space HA bold space bold space bold space bold space bold space bold space bold space bold space bold space harpoon to the right over harpoon to the left bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space H to the power of bold more bold space bold space bold space bold space bold space bold space bold space bold space bold space more bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space A to the power of bold less
Initial Molarity 0,020 0 0
ionization 0,001 0,001 0,001
Molarity in balance 0,019 0,001 0,001

In the example we have that the concentration of H ions+ é 0,001. Therefore, the pH of the solution is:

[H+] = 0,001 = 10-3

pH = - log 10-3 = 3

As the pH of the solution is less than 7, this solution is acidic.

Summary on pH and pOH

Definitions pH: hydrogen ionic potential of the solution.
pOH: hydroxylionic potential of the solution.
general formula pH + pOH = 14
Solutions Neutral pH = pOH = 7
acidic

pH

pOH > 7

basics

pOH

pH > 7

pH calculation pH = - log [H+]
Calculation of pOH pOH = -log[OH-]

Exercises on pH and pOH

1. (FMTM) The pH of gastric juice, an aqueous solution of hydrochloric acid (HCℓ), is approximately 2. Therefore, the mass, in grams, of HCℓ existing in each liter of gastric juice, is

Data: Molar masses (g/mol) H = 1, Cℓ = 35.5

a) 7.3 · 10-2
b) 3.65 · 10-1
c) 10-2
d) 2
e) 10

Correct alternative: b) 3.65 · 10-1.

1st step: calculate the concentration of H ions+.

pH space equal to space 2 space double arrow to the right parenthesis left square straight H to the power of plus right square bracket space equal to space 10 to the minus 2 power end of exponential mol space divided by straight L
space space HCl space space space space space right arrow space space space space straight H to the power of more space space space end of exponential space plus space space space Cl to the power of minus 10 to the power of minus 2 end of straight exponential M space space space space space space space 10 to minus 2 end of straight exponential M space space space 10 to minus 2 end of straight exponential M

2nd step: calculate the molar mass of HCl.

stack attributes charalign center stackalign right end attributes row 1 comma 0 nothing left parenthesis straight H right parenthesis end row row plus 35 comma 5 nothing left parenthesis Cl right parenthesis end row horizontal line row 36 comma 5 nothing left parenthesis HCl right parenthesis end row end stack

3rd step: calculate the mass of hydrochloric acid in each liter of gastric juice.

straight C with straight m subscript space equal to space numerator straight m over denominator straight M space. straight space V end of fraction 10 to the power of minus 2 end of exponential mol space divided by straight L space equal to space straight numerator m over denominator 36 comma 5 straight space g divided by mol space. space 1 straight L end of fraction straight m space equal to space 10 to the power of minus 2 end of exponential horizontal streaked space over mol divided by straight L end of streaked space. space 36 comma 5 straight space g divided by horizontal strikeout over mol end of strikeout space. space 1 horizontal line straight L straight m space equal to space 3 comma 65 space. space 10 to the power of minus 1 end of the straight exponential g

2. (UEMG) Several cleaning products have ammonia in their constitution. The label of one of these products indicates pH = 11. This means that the concentration of hydroxonium cations and hydroxyl anions in this product are, respectively:

to 1. 10-3 and 1. 10-11
b) 1. 10-11 and 1. 10-7
c) 1. 10-11 and 1. 10-3
d) 1. 10-11 and 1. 10-11

Correct alternative: c) 1. 10-11 and 1. 10-3.

a) WRONG. These concentrations correspond to a solution of pH = 3.

left square bracket H to the power of plus right square bracket space equals space 1.10 to the power of minus 3 end of exponential pH space equals space minus space log space left square bracket H to the power of plus right square bracket pH space equals space minus space log space 1.10 to the power of minus 3 end of exponential pH space equals space 3 left square bracket OH to the power of minus right square bracket space equals space 1.10 to the power of minus 11 end of exponential pOH space equals space minus space log space left square bracket OH to the power of minus right square bracket pOH space equals space minus space log space 1.10 to the power of minus 11 end of exponential pOH space equals space 11

b) WRONG. Although the concentration of H+ indicate that the pH of the solution is 11, the concentration of OH ions- is wrong, as it should be 3, since: pOH = 14 - pH.

left square bracket H to the power of plus right square bracket space equals space 1.10 to the power of minus 11 end of exponential pH space equals space minus space log space left square bracket H to the power of plus right square bracket pH space equals space minus space log space 1.10 to the power of minus 11 end of exponential pH space equals space 11 left square bracket OH to the power of minus right square bracket space equals space 1.10 to the power of minus 7 end of exponential pOH space equals space minus space log space left square bracket OH to the power of minus right square bracket pOH space equals space minus space log space 1.10 to the power of minus 7 end of exponential pOH space equals space 7

c) CORRECT. pH = 11 and pOH = 3, since pH + pOH = 14.

left square bracket H to the power of plus right square bracket space equals space 1.10 to the power of minus 11 end of exponential pH space equals space minus space log space left square bracket H to the power of plus right square bracket pH space equals space minus space log space 1.10 to the power of minus 11 end of exponential pH space equals space 11 left square bracket OH to the power of minus right square bracket space equals space 1.10 to the power of minus 3 end of exponential pOH space equals space minus space log space left square bracket OH to the power of minus right square bracket pOH space equals space minus space log space 1.10 to the power of minus 3 ends of the exponential pOH space equals space 3

d) WRONG. Although the concentration of H+ indicate that the pH of the solution is 11, the concentration of OH ions- is wrong, as it should be 3, since: pOH = 14 - pH.

left square bracket H to the power of plus right square bracket space equals space 1.10 to the power of minus 11 end of exponential pH space equals space minus space log space left square bracket H to the power of plus right square bracket pH space equals space minus space log space 1.10 to the power of minus 11 end of exponential pH space equals space 11 left square bracket OH to the power of minus right square bracket space equals space 1.10 to the power of minus 11 end of exponential pOH space equals space minus space log space left square bracket OH to the power of minus right square bracket pOH space equals space minus space log space 1.10 to the power of minus 11 end of exponential pOH space equals space 11
3. (UFRGS) Which of the following aqueous solutions has the highest pH?

a) 0.1 mol/L NaOH
b) NaCl 0.5 mol/L
c) H2ONLY4 1.0 mol/L
d) 1.0 mol/L HCl
e) 0.2 mol/L KOH

Correct alternative: e) KOH 0.2 mol/L.

a) WRONG. The solution is basic as its pH is greater than 7, but it does not have the higher pH of the alternatives.

space space space NaOH space space space space space space space space harpoon right on harpoon left space space space space space space space space space space Na to the power of more space space space space space space space space more space space space space space space space space OH at the power of minus 0 comma 1 space mol divided by straight L space space space space space space space space space space space space 0 comma 1 mol space divided by straight L space space space space space space space space space space 0 comma 1 mol space divided by straight L left square bracket OH to the power of minus right square bracket space equal to space 0 comma 1 space mol divided by straight L space equal to space 10 to the power of minus 1 space end of exponential mol divided by straight L pOH space space equal to space minus space log space parenthesis left straight line OH to the power of minus parenthesis right straight line space pOH space space equals space minus space log space 10 to the power of minus 1 end of the exponential space pOH space space equals space 1 pH space equals space pOH space equals space 14 pH space equals space 14 space less space pOH pH space equals space 14 space less space 1 pH space equal to space 13

b) WRONG. NaCl is a salt as it is the product of a strong acid and base reaction. Therefore, its pH is neutral.

HCl space plus space NaOH space right arrow space NaCl space plus space straight H with 2 subscript straight O

c) WRONG. Sulfuric acid is a strong acid, so its pH is low.

space space space straight H with 2 subscript SO with 4 subscript space space space space space space space harpoon right on harpoon left space space space space space space space space 2 straight H to the power of more space space space space space space space space more space space space space space space space space SO with 4 subscript with 2 minus superscript end of superscript space 1 comma 0 soft space divided by straight L space space space space space space space space space space space space space 2 comma 0 soft space divided by straight L space space space space space space space space space space 1 comma 0 soft space divided by straight L square bracket left straight H to the power of plus parenthesis right straight space equals space 2 comma 0 mol space divided by straight L space pH space space equals space minus log space space left square bracket square H to the power of plus right square bracket space pH space space equal to space minus space log space 2 space pH space space equal to space 0 comma 3

d) WRONG. Hydrochloric acid is a strong acid, so its pH is low.

space space space space space space space HCl space space space space space space space space harpoon right on harpoon left space space space space space space space space space space space space straight H to the power of more space space space space space space space space space space more space space space space space space space Cl to the power of minus space 1 comma 0 mol space divided by straight L space space space space space space space space space space space space space space 1 comma 0 soft space divided by straight L space space space space space space space space space space 1 comma 0 soft space divided by straight L left square bracket H to the power of plus right square bracket space equal to space 1 comma 0 mol space divided by straight L space pH space space equal to space less space log space left square bracket H to the power of more right square bracket space pH space space equal to space less space log space 1 space pH space space equals 0 space

e) CORRECT. The solution is basic as its pH is greater than 7.

space space space KOH space space space space space space space space harpoon right on harpoon left space space space space space space space space space space space space straight K to the power of more space space space space space space space space space space more space space space space space space space space OH at the power of minus 0 comma 2 soft space divided by straight L space space space space space space space space space space space space 0 comma 2 soft space divided by straight L space space space space space space space space space space 0 comma 2 mol space divided by straight L left square bracket OH to the minus power right bracket space equals space 0 comma 2 mol space divided by straight L space pOH space space equals space minus log space space left bracket OH to the power of minus right parenthesis space pOH space space equal to space minus space log space 0 comma 2 space pOH space space equal to space 0 comma 7 pH space more space pOH space equals space 14 pH space equals space 14 space less space pOH space equals space 14 space less space 0 comma 7 pH space equals space 13 comma 3
For more questions, with a commented resolution, be sure to check:Exercises on pH and pOH.
Stack: what it is, how it works and types

Stack: what it is, how it works and types

THE battery is a system where the oxidation-reduction reaction takes place. In this device, the c...

read more
Oxidation and reduction: what they are, examples and exercises

Oxidation and reduction: what they are, examples and exercises

THE oxidation and the reduction are reactions that occur when there is a electron transfer betwee...

read more