*Product Inequality*

Solving a product inequality consists in finding the values of x that satisfy the condition established by the inequality. For this we use the study of the sign of a function. Note the resolution of the following product equation: (2x + 6)*( – 3x + 12) > 0.

Let's establish the following functions: y_{1} = 2x + 6 and y_{2} = – 3x + 12.

Determining the root of the function (y = 0) and the position of the line (a > 0 increasing and a < 0 decreasing).

y_{1} = 2x + 6

2x + 6 = 0

2x = – 6

x = –3

y_{2} = – 3x + 12

–3x + 12 = 0

–3x = –12

x = 4

Checking the sign of the product inequality (2x + 6)*(– 3x + 12) > 0. Note that the product inequality requires the following condition: the possible values must be greater than zero, that is, positive.

Through the scheme that demonstrates the signs of the product inequality y1*y2, we can reach the following conclusion regarding the values of x: **x Є R / –3 < x < 4**

*quotient inequality*

In solving the quotient inequality we use the same resources as the product inequality, what differs is that, by we calculate the denominator function, we need to adopt values greater or less than zero and never equal to zero. Note the resolution of the following quotient inequality:

Solve the y functions

_{1}= x + 1 and y

_{2}= 2x – 1, determining the root of the function (y = 0) and the position of the line (a > 0 increasing and a < 0 decreasing).

y

_{1}= x + 1

x + 1 = 0

x = -1

y

_{2}= 2x - 1

2x - 1 = 0

2x = 1

x = 1/2

Based on the sign set, we conclude that x assumes the following values in the quotient inequality: **x Є R / –1 ≤ x < 1/2**

by Mark Noah

Graduated in Mathematics

Brazil School Team

**1st Degree Function - Roles - Math - Brazil School**

**Source:** Brazil School - https://brasilescola.uol.com.br/matematica/inequacao-produto-e-quociente.htm