Exercises on the area of ​​parallelograms

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You parallelogramsthey are polygons four-sided, which have opposite sides parallel, two by two. Examples of parallelograms are: o square, O rectangle it's the diamond.

The area (A) of any parallelogram corresponds to the measure of its surface and can be determined by the following formula:

\dpi{120} \mathbf{A = b \cdot h}

On what:

  • B: measure of the base of the parallelogram;
  • H: height of the parallelogram.

To learn more about this subject, check out a list of exercises on the parallelogram area, with all resolutions of the issues.

Index

  • Exercises on the area of ​​parallelograms
  • Resolution of question 1
  • Resolution of question 2
  • Resolution of question 3
  • Resolution of question 4

Exercises on the area of ​​parallelograms


Question 1. Determine the area of ​​the parallelogram with the dimensions shown in the figure below:

Parallelogram

Question 2. Determine the area of ​​the parallelogram with the dimensions shown in the figure below:

Parallelogram

Question 3. Determine the colored surface area of ​​the figure below:

Parallelogram

Question 4. Determine the area of ​​the parallelogram with dimensions shown in the figure below:

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Parallelogram

Resolution of question 1

We have b = 10 cm and h = 8 cm. Let's substitute these values ​​into the parallelogram area formula:

\dpi{120} \mathrm{A = b \cdot h}
\dpi{120} \Rightarrow \mathrm{A = 10 \cdot 8}
\dpi{120} \Rightarrow \mathrm{A = 80}

Therefore, the parallelogram area is equal to 80 cm².

Resolution of question 2

We have b = 8 cm and h = 12 cm. Let's substitute these values ​​into the parallelogram area formula:

\dpi{120} \mathrm{A = b \cdot h}
\dpi{120} \Rightarrow \mathrm{A = 8 \cdot 12}
\dpi{120} \Rightarrow \mathrm{A = 96}

Therefore, the parallelogram area is equal to 96 cm².

Resolution of question 3

The colored surface area corresponds to the area of ​​the major parallelogram minus the area of ​​the major parallelogram.

Let's calculate the area of ​​each parallelogram separately.

Larger parallelogram:

We have b = 7 cm + 2 cm = 9 cm and h = 10 cm + 1 cm = 11 cm. Let's substitute these values ​​into the parallelogram area formula:

\dpi{120} \mathrm{A = b \cdot h}
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\dpi{120} \Rightarrow \mathrm{A = 9 \cdot 11}
\dpi{120} \Rightarrow \mathrm{A = 99}

Minor parallelogram:

We have b = 7 cm and h = 10 cm. Let's substitute these values ​​into the parallelogram area formula:

\dpi{120} \mathrm{A = b \cdot h}
\dpi{120} \Rightarrow \mathrm{A = 7 \cdot 10}
\dpi{120} \Rightarrow \mathrm{A = 70}

So, the colored surface area is given by:

\dpi{120} \mathrm{A_{colored} = A_{larger} - A_{smaller}}
\dpi{120} \Rightarrow \mathrm{A_{colored} = 99 -70}
\dpi{120} \Rightarrow \mathrm{A_{colored} = 29}

Therefore, the colored surface area is equal to 29 cm².

Resolution of question 4

To calculate the area of ​​the parallelogram, we need to determine the measure of its base, that is, the measure of the side. \dpi{120} \overline{BC}.

Notice that \dpi{120} \overline{BC} = \overline{BH} + \overline{HC} .

Also, see that \dpi{120} \overline{BH} it is one of the legs of a right triangle, whose hypotenuse measures 13 cm and the other leg measures 12 cm.

So, by the Pythagorean theorem, We have to:

\dpi{120} \overline{BH} = \sqrt{13^2 - 12^2}
\dpi{120} \Rightarrow \overline{BH} = 5

Now, by the height theorem, we have to:

\dpi{120} 12^2 = \overline{BH}\cdot \overline{HC}
\dpi{120} \Rightarrow 12^2 = 5\cdot \overline{HC}
\dpi{120} \Rightarrow \overline{HC} = \frac{12^2}{5} = 28.8

We can already determine the measure of the base of the parallelogram:

\dpi{120} \overline{BC} = \overline{BH} + \overline{HC}
\dpi{120} \Rightarrow \overline{BC} = 5 + 28.8 = 33.8

Finally, we calculate your area:

\dpi{120} \mathrm{A = b \cdot h}
\dpi{120} \mathrm{A = 33.8 \cdot 12}
\dpi{120} \mathrm{A = 405.6}

Therefore, the parallelogram area is equal to 405.6 cm².

To download this list of the parallelogram area in PDF, click here!

You may also be interested:

  • circle area
  • trapeze area
  • Triangle Area

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