Exercises on 1st degree equation with an unknown

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Correct answers:

a) x = 9
b) x = 4
c) x = 6
d) x = 5

To solve an equation of the first degree we must isolate the unknown on one side of the equality and the constant values ​​on the other. Remember that when changing a term in the equation to the other side of the equals sign, we must reverse the operation. For example, what was adding starts to subtract and vice versa.

a) Correct answer: x = 9.

4 straight x space plus space 2 space equals space 38 4 straight x space equals space 38 space minus space 2 4 straight x space equal to space 36 straight x space equal to space 36 over 4 straight x space equal to space 9

b) Correct answer: x = 4

9 straight x space equal to space 6 straight x space plus space 12 9 straight x space minus space 6 straight x equal space a space 12 3 straight x space equal to space 12 straight x space equal to space 12 over 3 straight x space equal to space 4

c) Correct answer: x = 6

5 straight x space – space 1 space equal to space 3 straight x space plus space 11 5 straight x space minus space 3 straight x space equal to space 11 space plus space 1 2 straight x space equal to space 12 straight x space equal to space 12 over 2 straight x space equal to space 6

d) Correct answer: x = 5

2 straight x space plus space 8 space equal to space straight x space plus space 13 2 straight x space minus straight space x space equal to space 13 space minus space 8 straight x space equal to space 5

Correct answer: x = - 6/11.

First, we must eliminate the parentheses. For this, we apply the distributive property of multiplication.

4. left parenthesis square x space – space 2 right parenthesis space – space 5. left parenthesis 2 space – space 3 straight x right parenthesis space equals 4 space. left parenthesis 2 straight x space – space 6 right parenthesis 4 straight x space minus space 8 space minus space 10 space plus space 15 straight x space equal to space 8 straight x space minus space 24 19 straight x space minus space 18 space equal to space 8 straight x space minus space 24

Now we can find the unknown value by isolating the x on one side of the equality.

19 straight x space minus space 8 straight x space equals space minus space 24 space plus space 18 11 straight x space equals space minus space 6 straight x space equals space minus space 6 over 11

Correct answer: 11/3.

Note that the equation has fractions. To solve it we first need to reduce the fractions to the same denominator. Therefore, we must calculate the least common multiple between them.

table row with 4 3 2 row with 2 3 1 row with 1 3 1 row with 1 1 1 end of table in right frame closes frame table row with 2 row with 2 row with 3 row with cell with 2 straight space x space 2 straight space x space 3 space equal to space 12in top frame close frame end of cell end of table

Now we divide the MMC 12 by the denominator of each fraction and the result must be multiplied by the numerator. This value becomes the numerator, while the denominator of all terms is 12.

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numerator 2 straight x over denominator 4 end of fraction space – space 5 over 3 space equal to space straight x space – space 7 over 2 space double arrow right arrow double right numerator 3.2 straight x over denominator 12 end of fraction space – space numerator 4.5 over denominator 12 end of fraction space equal to space numerator 12. straight x over denominator 12 end of fraction space – space numerator 6.7 over denominator 12 end of fraction double arrow right double arrow right numerator 6 straight x over denominator 12 end of fraction space – space 20 over 12 space equal to space numerator 12 straight x over denominator 12 end of fraction space – space 42 over 12

After canceling the denominators, we can isolate the unknown and calculate the value of x.

6 straight x space minus space 20 space equals space 12 straight x space minus space 42 6 straight x space minus space 12 straight x space equals space minus space 42 space plus space 20 minus space 6 straight x space equals space minus space 22 space. left parenthesis minus 1 right parenthesis 6 straight x space equals space 22 straight x space equals space 22 over 6 equals 11 over 3

Correct answer: - 1/3.

1st step: calculate the MMC of the denominators.

table row with 3 6 2 row with 3 3 1 row with 1 1 1 row with blank blank blank end of table in right frame closes frame table row with 2 row with 3 row with cell with 2 space straight x space 3 space equal to space 6in top frame close frame end of cell row with blank end of table

2nd step: divide the MMC by the denominator of each fraction and multiply the result by the numerator. After that, we replace the numerator with the result calculated previously and the denominator with the MMC.

numerator 4 straight x space plus space 2 over denominator 3 end of fraction space – numerator 5 straight x space – space 7 over denominator 6 end of fraction space equal to space numerator 3 space – straight space x over denominator 2 end of fraction right double arrow right double arrow numerator 2. left parenthesis 4 straight x space plus space 2 right parenthesis over denominator 6 end of fraction space – numerator space 5 straight x space – space 7 over denominator 6 end of fraction space equal to numerator space 3. left parenthesis 3 space – straight space x right parenthesis over denominator 6 end of fraction double arrow right double arrow to the right numerator 8 straight x space plus space 4 over denominator 6 end of fraction space – numerator space 5 straight x space – space 7 over denominator 6 end of fraction space equal to space numerator 9 space – space 3 straight x over denominator 6 end of fraction

3rd step: cancel the denominator, isolate the unknown and calculate its value.

8 straight x space plus space 4 space minus space left parenthesis 5 straight x space minus space 7 right parenthesis equals space 9 space minus space 3 straight x
The minus sign before the parentheses changes the signs of the terms inside.
-1. 5x = -5x
-1. (-7) = 7
Continuing the equation:


8 straight x space plus space 4 space minus space 5 straight x space plus space 7 equals space 9 space minus space 3 straight x space 3 straight x space plus space 11 space equal to space 9 space minus space 3 straight x space 3 straight x space plus space 3 straight x space equal to space 9 space minus space 11 space 6 straight x space equal to space minus space 2 straight space x space equal to space numerator minus 2 over denominator 6 end of fraction equals space numerator minus 1 over denominator 3 end of fraction

Correct answers:

a) y = 2
b) x = 6
c) y.x = 12
d) y/x = 1/3

a) y = 2

5 straight y space plus space 2 space equals space 8 straight y space – space 4 5 straight y space minus space 8 straight y space equals space minus 4 space minus 2 minus space 3 straight y space equals space minus space 6 space. left parenthesis minus 1 right parenthesis 3 straight y space equals space 6 straight y space equals space 6 over 3 straight y space equals space 2

b) x = 6

4 straight x space – space 2 space equal to space 3 straight x space plus space 4 4 ​​straight x space minus space 3 straight x space equal to space 4 space plus space 2 straight x space equal to space 6

c) y.x = 12

y. x = 2. 6 = 12

d) y/x = 1/3

straight y over straight x space equal to space 2 over 6 equal to 1 third

Correct answer: b) 38.

To build an equation there must be two members: one before and one after the equals sign. Each component of the equation is called a term.

The terms in the first member of the equation are double the unknown number and 6 units. The values ​​must be added, therefore: 2x + 6.

The second member of the equation contains the result of this operation, which is 82. Assembling the equation of the first degree with an unknown, we have:

2x + 6 = 82

Now, we solve the equation by isolating the unknown in one member and transferring the number 6 to the second member. To do this, the number 6, which was positive, becomes negative.

2x + 6 = 82
2x = 82 - 6
2x = 76
x = 38

So the unknown number is 38.

Correct answer: d) 20.

The perimeter of a rectangle is the sum of its sides. The long side is called the base and the short side is called the height.

According to the statement data, if the short side of the rectangle is x, then the long side is (x + 10).

A rectangle is a quadrilateral, so its perimeter is the sum of the two longest sides and the two shortest sides. This can be expressed in equation form as follows:

2x + 2(x+10) = 100

To find the measure of the short side, just solve the equation.

2x + 2(x+10) = 100
2x + 2x + 20 = 100
4x = 100 - 20
4x = 80
x = 80/4
x = 20

Correct alternative: c) 40.

We can use the unknown x to represent the original length of the piece. Thus, after being washed, the piece lost 1/10 of its x length.

The first way you can resolve this issue is:

x - 0.1x = 36
0.9x = 36
x = 36/0.9
x = 40

The second form, on the other hand, needs the mmc of the denominators, which is 10.

Now we calculate the new numerators by dividing the mmc by the initial denominator and multiplying the result by the initial numerator. After that, we cancel the denominator 10 of all terms and solve the equation.

straight x space – straight x space over 10 space equal to space 36 space left parenthesis mmc space 10 right parenthesis space space 10 straight x space – space straight x space equal to space 360 ​​space space 9 straight x space equal to space 360 ​​space straight space x space equal to space 360 ​​over 9 straight x space equal to space 40

Therefore, the original length of the piece was 40 m.

Correct alternative: c) 2310 m.

Since the total path is the unknown value, let's call it x.

The terms of the first member of the equation are:

  • Race: 2/7x
  • Walk: 5/11x
  • additional stretch: 600

The sums of all these values ​​result in the length of the run, which we call x. Therefore, the equation can be written as:

2/7x + 5/11x + 600 = x

To solve this equation of the first degree we need to calculate the mmc of the denominators.

mmc (7.11) = 77

Now we replace the terms in the equation.

numerator 11.2 straight x over denominator 77 end of fraction plus space numerator 7.5 straight x over denominator 77 end of fraction space plus numerator space 77,600 over denominator 77 end of fraction equals numerator space 77. straight x over denominator 77 end of fraction 22 straight x space plus space 35 straight x space plus space 46200 space equal to space 77 straight x space space 57 straight x space plus space 46200 space equals space 77 straight x space 46200 space equals space 77 straight x space – space 57 straight x space space 46200 space equal to space 20 straight x space straight space x space equal to space 46200 over 20 straight x space equal to space 2310 space straight m

Therefore, the total length of the path is 2310 m.

Correct alternative: c) 300.

If B's ​​number of hits was x, then A's number of hits was x + 40%. This percentage can be written as the fraction 40/100 or as the decimal number 0.40.

Therefore, the equation that determines the number of correct answers can be:

x + x + 40/100x = 720 or x + x + 0.40x = 720

Resolution 1:

straight x space plus space straight x space plus numerator space 40 over denominator 100 end of fraction straight x space equal to space 720 space left parenthesis mmc space 100 right parenthesis space space 100 straight x space plus space 100 straight x space plus space 40 straight x space equal to space 72000 space space 240 straight x space equal to space 72000 straight space x space equal to space 72000 over 240 straight x space equal to space 300

Resolution 2:

straight x space plus space straight x space plus space 0 comma 4 straight x space equals space 720 space space 2 comma 4 straight x space equals space 720 space straight space x space equal to space numerator 720 over denominator 2 comma 4 end of fraction straight x space equal to space numerator 720 over denominator start style show typographic 24 over 10 end style end of fraction space straight space x space equal to space 720 space. space 10 over 24 space straight space x space equal to space 7200 over 24 straight space x space equal to space 300

Therefore, B's number of hits was 300.

Correct answer: 9, 10, 11, 12, 13, 14 and 15.

By assigning the unknown x to the first number in the sequence, then the number's successor is x+1, and so on.

The first member of the equation is formed by the sum of the first four numbers in the sequence and the second member, after equality, presents the last three. So we can write the equation like this:

x + (x+1) + (x+2) + (x+3) = (x+4) + (x+5) + (x+6)
4x + 6 = 3x + 15
4x - 3x = 15 - 6
x = 9

Thus, the first term is 9 and the sequence is formed by the seven numbers: 9, 10, 11, 12, 13, 14 and 15.

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